\(\int (a+a \cos (e+f x))^m (A+C \cos ^2(e+f x)) \, dx\) [198]

   Optimal result
   Rubi [A] (verified)
   Mathematica [C] (warning: unable to verify)
   Maple [F]
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 25, antiderivative size = 170 \[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=-\frac {C (a+a \cos (e+f x))^m \sin (e+f x)}{f \left (2+3 m+m^2\right )}+\frac {C (a+a \cos (e+f x))^{1+m} \sin (e+f x)}{a f (2+m)}+\frac {2^{\frac {1}{2}+m} \left (C \left (1+m+m^2\right )+A \left (2+3 m+m^2\right )\right ) (1+\cos (e+f x))^{-\frac {1}{2}-m} (a+a \cos (e+f x))^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2}-m,\frac {3}{2},\frac {1}{2} (1-\cos (e+f x))\right ) \sin (e+f x)}{f (1+m) (2+m)} \]

[Out]

-C*(a+a*cos(f*x+e))^m*sin(f*x+e)/f/(m^2+3*m+2)+C*(a+a*cos(f*x+e))^(1+m)*sin(f*x+e)/a/f/(2+m)+2^(1/2+m)*(C*(m^2
+m+1)+A*(m^2+3*m+2))*(1+cos(f*x+e))^(-1/2-m)*(a+a*cos(f*x+e))^m*hypergeom([1/2, 1/2-m],[3/2],1/2-1/2*cos(f*x+e
))*sin(f*x+e)/f/(m^2+3*m+2)

Rubi [A] (verified)

Time = 0.23 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {3103, 2830, 2731, 2730} \[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=\frac {2^{m+\frac {1}{2}} \left (A \left (m^2+3 m+2\right )+C \left (m^2+m+1\right )\right ) \sin (e+f x) (\cos (e+f x)+1)^{-m-\frac {1}{2}} (a \cos (e+f x)+a)^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2}-m,\frac {3}{2},\frac {1}{2} (1-\cos (e+f x))\right )}{f (m+1) (m+2)}-\frac {C \sin (e+f x) (a \cos (e+f x)+a)^m}{f \left (m^2+3 m+2\right )}+\frac {C \sin (e+f x) (a \cos (e+f x)+a)^{m+1}}{a f (m+2)} \]

[In]

Int[(a + a*Cos[e + f*x])^m*(A + C*Cos[e + f*x]^2),x]

[Out]

-((C*(a + a*Cos[e + f*x])^m*Sin[e + f*x])/(f*(2 + 3*m + m^2))) + (C*(a + a*Cos[e + f*x])^(1 + m)*Sin[e + f*x])
/(a*f*(2 + m)) + (2^(1/2 + m)*(C*(1 + m + m^2) + A*(2 + 3*m + m^2))*(1 + Cos[e + f*x])^(-1/2 - m)*(a + a*Cos[e
 + f*x])^m*Hypergeometric2F1[1/2, 1/2 - m, 3/2, (1 - Cos[e + f*x])/2]*Sin[e + f*x])/(f*(1 + m)*(2 + m))

Rule 2730

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-2^(n + 1/2))*a^(n - 1/2)*b*(Cos[c + d*x]/
(d*Sqrt[a + b*Sin[c + d*x]]))*Hypergeometric2F1[1/2, 1/2 - n, 3/2, (1/2)*(1 - b*(Sin[c + d*x]/a))], x] /; Free
Q[{a, b, c, d, n}, x] && EqQ[a^2 - b^2, 0] &&  !IntegerQ[2*n] && GtQ[a, 0]

Rule 2731

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[a^IntPart[n]*((a + b*Sin[c + d*x])^FracPart
[n]/(1 + (b/a)*Sin[c + d*x])^FracPart[n]), Int[(1 + (b/a)*Sin[c + d*x])^n, x], x] /; FreeQ[{a, b, c, d, n}, x]
 && EqQ[a^2 - b^2, 0] &&  !IntegerQ[2*n] &&  !GtQ[a, 0]

Rule 2830

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-d
)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/(f*(m + 1))), x] + Dist[(a*d*m + b*c*(m + 1))/(b*(m + 1)), Int[(a + b*S
in[e + f*x])^m, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] &&  !LtQ[m
, -2^(-1)]

Rule 3103

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[
(-C)*Cos[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Dist[1/(b*(m + 2)), Int[(a + b*Sin[e + f*
x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) - a*C*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, C, m}, x] &&  !Lt
Q[m, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {C (a+a \cos (e+f x))^{1+m} \sin (e+f x)}{a f (2+m)}+\frac {\int (a+a \cos (e+f x))^m (a (C (1+m)+A (2+m))-a C \cos (e+f x)) \, dx}{a (2+m)} \\ & = -\frac {C (a+a \cos (e+f x))^m \sin (e+f x)}{f \left (2+3 m+m^2\right )}+\frac {C (a+a \cos (e+f x))^{1+m} \sin (e+f x)}{a f (2+m)}+\frac {\left (C \left (1+m+m^2\right )+A \left (2+3 m+m^2\right )\right ) \int (a+a \cos (e+f x))^m \, dx}{(1+m) (2+m)} \\ & = -\frac {C (a+a \cos (e+f x))^m \sin (e+f x)}{f \left (2+3 m+m^2\right )}+\frac {C (a+a \cos (e+f x))^{1+m} \sin (e+f x)}{a f (2+m)}+\frac {\left (\left (C \left (1+m+m^2\right )+A \left (2+3 m+m^2\right )\right ) (1+\cos (e+f x))^{-m} (a+a \cos (e+f x))^m\right ) \int (1+\cos (e+f x))^m \, dx}{(1+m) (2+m)} \\ & = -\frac {C (a+a \cos (e+f x))^m \sin (e+f x)}{f \left (2+3 m+m^2\right )}+\frac {C (a+a \cos (e+f x))^{1+m} \sin (e+f x)}{a f (2+m)}+\frac {2^{\frac {1}{2}+m} \left (C \left (1+m+m^2\right )+A \left (2+3 m+m^2\right )\right ) (1+\cos (e+f x))^{-\frac {1}{2}-m} (a+a \cos (e+f x))^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2}-m,\frac {3}{2},\frac {1}{2} (1-\cos (e+f x))\right ) \sin (e+f x)}{f (1+m) (2+m)} \\ \end{align*}

Mathematica [C] (warning: unable to verify)

Result contains complex when optimal does not.

Time = 1.29 (sec) , antiderivative size = 242, normalized size of antiderivative = 1.42 \[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=\frac {i 4^{-1-m} e^{-i (2+m) (e+f x)} \left (1+e^{i (e+f x)}\right ) \left (e^{-\frac {1}{2} i (e+f x)} \left (1+e^{i (e+f x)}\right )\right )^{2 m} \cos ^{-2 m}\left (\frac {1}{2} (e+f x)\right ) (a (1+\cos (e+f x)))^m \left (C e^{i m (e+f x)} (-2+m) m \operatorname {Hypergeometric2F1}\left (1,-1+m,-1-m,-e^{i (e+f x)}\right )+e^{i (2+m) (e+f x)} (2+m) \left (2 (2 A+C) (-2+m) \operatorname {Hypergeometric2F1}\left (1,1+m,1-m,-e^{i (e+f x)}\right )+C e^{2 i (e+f x)} m \operatorname {Hypergeometric2F1}\left (1,3+m,3-m,-e^{i (e+f x)}\right )\right )\right )}{f (-2+m) m (2+m)} \]

[In]

Integrate[(a + a*Cos[e + f*x])^m*(A + C*Cos[e + f*x]^2),x]

[Out]

(I*4^(-1 - m)*(1 + E^(I*(e + f*x)))*((1 + E^(I*(e + f*x)))/E^((I/2)*(e + f*x)))^(2*m)*(a*(1 + Cos[e + f*x]))^m
*(C*E^(I*m*(e + f*x))*(-2 + m)*m*Hypergeometric2F1[1, -1 + m, -1 - m, -E^(I*(e + f*x))] + E^(I*(2 + m)*(e + f*
x))*(2 + m)*(2*(2*A + C)*(-2 + m)*Hypergeometric2F1[1, 1 + m, 1 - m, -E^(I*(e + f*x))] + C*E^((2*I)*(e + f*x))
*m*Hypergeometric2F1[1, 3 + m, 3 - m, -E^(I*(e + f*x))])))/(E^(I*(2 + m)*(e + f*x))*f*(-2 + m)*m*(2 + m)*Cos[(
e + f*x)/2]^(2*m))

Maple [F]

\[\int \left (a +\cos \left (f x +e \right ) a \right )^{m} \left (A +C \left (\cos ^{2}\left (f x +e \right )\right )\right )d x\]

[In]

int((a+cos(f*x+e)*a)^m*(A+C*cos(f*x+e)^2),x)

[Out]

int((a+cos(f*x+e)*a)^m*(A+C*cos(f*x+e)^2),x)

Fricas [F]

\[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=\int { {\left (C \cos \left (f x + e\right )^{2} + A\right )} {\left (a \cos \left (f x + e\right ) + a\right )}^{m} \,d x } \]

[In]

integrate((a+a*cos(f*x+e))^m*(A+C*cos(f*x+e)^2),x, algorithm="fricas")

[Out]

integral((C*cos(f*x + e)^2 + A)*(a*cos(f*x + e) + a)^m, x)

Sympy [F]

\[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=\int \left (a \left (\cos {\left (e + f x \right )} + 1\right )\right )^{m} \left (A + C \cos ^{2}{\left (e + f x \right )}\right )\, dx \]

[In]

integrate((a+a*cos(f*x+e))**m*(A+C*cos(f*x+e)**2),x)

[Out]

Integral((a*(cos(e + f*x) + 1))**m*(A + C*cos(e + f*x)**2), x)

Maxima [F]

\[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=\int { {\left (C \cos \left (f x + e\right )^{2} + A\right )} {\left (a \cos \left (f x + e\right ) + a\right )}^{m} \,d x } \]

[In]

integrate((a+a*cos(f*x+e))^m*(A+C*cos(f*x+e)^2),x, algorithm="maxima")

[Out]

integrate((C*cos(f*x + e)^2 + A)*(a*cos(f*x + e) + a)^m, x)

Giac [F]

\[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=\int { {\left (C \cos \left (f x + e\right )^{2} + A\right )} {\left (a \cos \left (f x + e\right ) + a\right )}^{m} \,d x } \]

[In]

integrate((a+a*cos(f*x+e))^m*(A+C*cos(f*x+e)^2),x, algorithm="giac")

[Out]

integrate((C*cos(f*x + e)^2 + A)*(a*cos(f*x + e) + a)^m, x)

Mupad [F(-1)]

Timed out. \[ \int (a+a \cos (e+f x))^m \left (A+C \cos ^2(e+f x)\right ) \, dx=\int \left (C\,{\cos \left (e+f\,x\right )}^2+A\right )\,{\left (a+a\,\cos \left (e+f\,x\right )\right )}^m \,d x \]

[In]

int((A + C*cos(e + f*x)^2)*(a + a*cos(e + f*x))^m,x)

[Out]

int((A + C*cos(e + f*x)^2)*(a + a*cos(e + f*x))^m, x)